Two rectangles have the same width. One is 12 units long and the other is 8 units long. The area of the first rectangle is 320 square units more than the area of the second rectangle. Find the width of each rectangle.

Respuesta :

Answer:

80

Step-by-step explanation:

let w = the width of the rectangles

then

12w = the area of one rectangle

8w = the area of other

:

12w - 8w = 320

4w = 320

w = 320/4

w = 80 units wide

;

:

Check

12 * 80 = 960

8 * 80 = 640

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difference: 320

We know that both rectangles have the same width, which is 80 units.

How to find the width of each rectangle?

We know that both rectangles have the same width, so we can say that both have the width W.

One of the rectangles has a length of 12 units, and the other of 8 units, so the areas are:

A = 12*W

A' = 8*W

And the largest area is 320 square units more than the other area, so we have:

12*W = 8*W + 320

Solving for W we get:

12*W - 8*W = 320

4*W = 320

W = 320/4 = 80

Then the width of each rectangle is 80 units.

If you want to learn more about rectangles:

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