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Select the true statement for the following reaction: N2 + 3 H2 → 2 NH3 1. Each N atom is reduced from 0 to +3. Each H atom is oxidized from 0 to −1. 2. Each N atom is reduced from 0 to −3. Each H atom is oxidized from 0 to +1. 3. Each N atom is oxidized from 0 to +3. Each H atom is reduced from 0 to −1. 4. Each N atom is oxidized from 0 to −3. Each H atom is reduced from 0 to +1. 5. Each N atom is reduced from +1 to −3. Each H atom is oxidized from +1 to 0. 6. Each N atom is oxidized from +1 to +3. Each H atom is reduced from +1 to 0. 7. Each N atom is oxidized from 0 to −6. Each H atom is reduced from 0 to +2. 8. Each N atom is reduced from 0 to −6

Respuesta :

Answer: option 2

Explanation: each nitrogen is reduced from zero to -3 and Each H is Oxidised from 0 to +1

Since oxidation no of Nitrogen in molecular N2 is always zero and for H2 also zero.

In NH3, x+3(+1)=0

X+3=0

X=-3

And and hydrogen shows +1 Oxidation no when it is combined with non metal(like N,O,cl) and with -2 with metal like Na,Ca etc.

And zero in molecular form H2.

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