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jturner10659

Hello i hope you are having a good day :) Question : A 60.0 kg runner is moving at 6.00 m/s and speeds up to 9.00 m/s. The runner’s change in kinetic energy is 1,350 J? = firstly you would need to change the kinetic energy meaning that would be a kinetic energy of 1/2mv^2  so now you would do the m which would be for the mass and the v is the velocity as well the initial of k.e that would be 1/2 x 60 x 6^2 that would equal too = 1,080j Final K.E = 1/2 × 60 × 9² = 2,430 J Work done = change in kinetic energy. = 2,430 - 1,080 = 1,350 J.

Hopefully that helps you.

The change in the kinetic energy of the runner will be 1350 J. It is found by subtracting the kinetic energy during two different velocity.

What is kinetic energy?

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

According to the law of conservation of energy, the total energy is defined as the sum of kinetic energy and potential energy.

The change in the kinetic energy is found as;

[tex]\rm KE = \frac{1}{2} m(v^2-u^2)\\\\ KE = \frac{1}{2} \times 60 (9^2-6^2) \\\\ KE=1350 \ J[/tex]

Hence, the change in the kinetic energy of the runner will be 1350 J.

To learn more about kinetic energy, refer to the link;

brainly.com/question/999862

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