For this case we have that the surface area of the figure is given by the surface area of a cone plus the surface area of a cylinder.
The surface area of a cylinder is given by:
[tex]SA = 2 \pi * r * h + 2 \pi * r ^ 2[/tex]
Where:
h: It's the height
A: It's the radio.
Substituting the values:
[tex]SA = 2 \pi * 1 * 3 + 2 \pi * 1 ^ 2\\SA = 6 \pi + 2 \pi * 1\\SA = 8 \pi\\SA = 25.12 \ units ^ 2[/tex]
On the other hand, the surface area of a cone is given by:
[tex]SA = \pi * r * s + \pi * r ^ 2[/tex]
Where:
A: It's the radio
s: inclination
Substituting the values:
S[tex]A = \pi * 1 * 6 + \pi * 1 ^ 2\\SA = 6 \pi + \pi\\SA = 7 \pi[/tex]
[tex]SA = 21.98 \ units ^ 2[/tex]
Thus, the surface area of the figure is:
[tex]47.1 \ units ^ 2[/tex]
ANswer:
[tex]47.1 \ units ^ 2[/tex]
