Answer:
[tex]3a^4[/tex]
Step-by-step explanation:
Given expression is [tex]27a^{12}[/tex].
Now we need to find the cube root of given expression [tex]27a^{12}[/tex].
[tex]\sqrt[3]{27a^{12}}[/tex]
[tex]=\sqrt[3]{3*3*3a^{4*3}}[/tex]
[tex]=\sqrt[3]{3^3\left(a^4\right)^3}[/tex]
[tex]=\sqrt[3]{\left(3a^4\right)^3}[/tex]
Since cube root and cube are opposite operations of each other. So they will cancel each other.
[tex]=3a^4[/tex]
Hence correct choice is the last choice [tex]3a^4[/tex].
