Answer:
1097.8 V/m
Explanation:
The equation that relates the intensity of an electromagnetic wave with the magnitude of the electric field is:
[tex]I=\frac{1}{2}c\epsilon_0 E^2[/tex]
where
c is the speed of light
[tex]\epsilon_0[/tex] is the vacuum permittivity
E is the peak magnitude of the electric field
In this problem, we know the intensity:
I = 1600 W/m^2
So we can rearrange the formula to find E:
[tex]E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1600 W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=1097.8 V/m[/tex]
