The average maximum height of the beanbag when the speed of the bottle is 2 m/s would be equal to 0.2 meter.
Scientific data:
- Acceleration due to gravity (g) = 10 [tex]m/s^2[/tex].
How to calculate the average maximum height.
In order to determine the average maximum height of the beanbag, we would apply the third equation of motion:
[tex]V^2=U^2+2gH\\\\V^2=0^2+2gH\\\\H=\frac{V^2}{2g}[/tex]
Note: U is the initial speed and it should be equal to 0 m/s.
When V = 2 m/s:
[tex]H=\frac{2^2}{2 \times 10} \\\\H=\frac{4}{20}[/tex]
H = 0.2 meter.
When V = 3 m/s:
[tex]H=\frac{3^2}{2 \times 10} \\\\H=\frac{9}{20}[/tex]
H = 0.45 meter.
When V = 4 m/s:
[tex]H=\frac{4^2}{2 \times 10} \\\\H=\frac{16}{20}[/tex]
H = 0.8 meter.
When V = 5 m/s:
[tex]H=\frac{5^2}{2 \times 10} \\\\H=\frac{25}{20}[/tex]
H = 1.25 meter.
When V = 6 m/s:
[tex]H=\frac{6^2}{2 \times 10} \\\\H=\frac{36}{20}[/tex]
H = 1.8 meter.
Read more on speed here: brainly.com/question/10545161
