Respuesta :

Answer:  [tex]\bold{B)\quad \dfrac{x-2}{x+1}}[/tex]

Step-by-step explanation:

[tex]\dfrac{x^2+5x-14}{x^2+8x+7}\\\\\\=\dfrac{(x+7)(x-2)}{(x+7)(x+1)}\\\\\\=\dfrac{x-2}{x+1}[/tex]