Answer:
5 between Martin's place and the school
Step-by-step explanation:
I don't know if you can draw a diagram from by directions, but you can try. It will help you to see the problem.
Draw
Draw a line that looks like this on your paper.
<===============:
school X Martin's place
Now draw a line going upwards from the arrow head.
∧ Haley's place.
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<=============:
school x Martin's place
Label the distance from the school to Haley's place as 12
I can't draw a line between martin's place and Haley's but you can. Label it as 13
So the givens are
c = distance between Haley's place and Martin's = 13
b= distance from the school to Haley's is 12
a = ? Distance from Martin't and the school = x
Formula
c^2 = a^2 + b^2
Solution
13^2 = 12^2 + a^2
169 = 144 + a^2 Subtract 144 from both sides.
169 - 144 = 144 - 144 + a^2
25 = a^2
sqrt(25) = sqrt(a^2)
a = 5
