Answer:
[tex]\boxed{\text{112 K}}[/tex]
Explanation:
A) Know
p₁ = Initial pressure; p₂ = final pressure
V₁ =Initial volume; V₂ = final pressure
T₁ = Initial temperature
B) Find
T₂ = final temperature
C) Strategy
Use the Combined Gas Laws Equation:
[tex]\dfrac{p_{1}V_{1}}{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}[/tex]
It contains symbols for all the knowns and the unknown.
D) Calculations
(i) Data:
p₁ = 3.5 atm; p₂ = 1.5 L
V₁ = 3.2 L; V₂ = 2.6 L
T₁ = 323 K T₂ = ?
(ii) Calculation
[tex]\dfrac{3.5\times3.2}{323} = \dfrac{1.5\times 2.6}{T_{2}}\\\\0.0347 = \dfrac{3.90}{T_{2}}\\\\T_{2} = \dfrac{3.90}{0.0347} = \boxed{\textbf{112 K}}[/tex]
