jetblackcap jetblackcap
  • 12-05-2019
  • Mathematics
contestada

Please please help me

Please please help me class=

Respuesta :

jimrgrant1 jimrgrant1
  • 12-05-2019

Answer:

[tex]\frac{\sqrt{11} }{6}[/tex]

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

cosx = [tex]\sqrt{1-sin^2x}[/tex]

cosΘ = [tex]\sqrt{1-(5/6)^2}[/tex]

         = [tex]\sqrt{1-\frac{25}{36} }[/tex] = [tex]\sqrt{\frac{11}{36} }[/tex] = [tex]\frac{\sqrt{11} }{6}[/tex]

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