Answer:
The triangle does not exist because sin(A)/a can not be equal to sin(B)/b
Step-by-step explanation:
we know that
step 1
Find the measure of angle B
Applying the law of sines
[tex]\frac{sin(A)}{a}=\frac{sin(B)}{b}[/tex]
we have
[tex]A=30\°[/tex]
[tex]sin(30\°)=1/2[/tex]
[tex]a=6\ units[/tex]
[tex]b=18\ units[/tex]
substitute
[tex]\frac{(1/2)}{6}=\frac{sin(B)}{18}[/tex]
[tex]\frac{1}{12}=\frac{sin(B)}{18}[/tex]
[tex]sin(B)=\frac{18}{12}[/tex]
[tex]sin(B)=\frac{3}{2}=1.5[/tex]
Remember that the value of sine can not be greater than 1
therefore
The triangle does not exist because sin(A)/a can not be equal to sin(B)/b
