Answer:
The area of the kite is [tex]42\ units^{2}[/tex]
Step-by-step explanation:
see the attached figure with letters to better understand the problem
we know that
The area of the kite is equal to
[tex]A=\frac{1}{2}(AC*BD)[/tex]
we have
BE=ED
[tex]BD=3*2=6\ units[/tex]
[tex]AC=AE+10[/tex]
In the right triangle AEB
Applying the Pythagoras Theorem find AE
[tex]AE^{2}=5^{2}-3^{2}[/tex]
[tex]AE^{2}=16[/tex]
[tex]AE=4\ units[/tex]
Find AC
[tex]AC=4+10=14\ units[/tex]
Find the area of the kite
[tex]A=\frac{1}{2}(14*6)=42\ units^{2}[/tex]
