Answer:
6 cm
Step-by-step explanation:
If you use Tangent-secant product (chapter reference), AB/AC = AD/AB so 4/2 = AD/4. AD = 8, CD = AD - AC = 8 - 2 = 6 cm.
The square of the measure of the tangent segment is equal to the product of measure of the secant segment and its external secant segment. Then the length of AD is 8 cm.
It is a locus of a point drawn at an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
AB tangent to circle O at B, and secant through point A intersect the circle at points C and D.
AB = 4 cm
AC = 2 cm
The square of the measure of the tangent segment is equal to the product of measure of the secant segment and its external secant segment. That is given as
AC × AD = AB²
2 × AD = 4²
2 × AD = 16
AD = 8
Thus, the length of AD is 8 cm.
More about the circle link is given below.
https://brainly.com/question/11833983
