Answer:
Dimensions of photo excluding border:
x = 11 inches
y = 6 inches
Step-by-step explanation:
Let the length be 'x' and width be 'y'.
The width of a photo is 5 inches less than its length, that is:
x-5 = y
let 'X' be length of photo including border and 'Y' be the width of photo including border:
Where X = x+2 and Y = y+2
Now , we have X-5 = Y
and X*Y = 104 square inches
*putting Y = X-5*
X(X-5) = 104
[tex]X^2 - 5X - 104 = 0[/tex]
[tex]X^2 - 13X + 8X - 104 = [/tex]
[tex]X(X-13)+8(X-13) = 0\\(X-13)(X+8)[/tex]
⇒ X-13 = 0 or X+8 = 0
Hence X = 13 or X = -8
As length can not be negative, X = 13 inches
Y = X-5 = 13-5 = 8 inches
Dimensions of photo excluding border:
x = X - 2 = 13-2 = 11 inches
y = Y-2 = 8-2 = 6 inches
