Respuesta :
Answer:
The shoe hit the disc.
Step-by-step explanation:
Let [tex]ax ^ 2 + bx + c[/tex] be a quadratic function where a, b and c are the real coefficients of the function.
Then the discriminant of the function is:
[tex]b ^ 2 - 4ac[/tex]
The result of this expression gives us information about the roots of this equation.
* If the discriminant is > 0 then the equation has 2 real solutions
* If the discriminant is > 0 then the equation has 2 complex solutions
* If the discriminant is = 0 then the equation has 1 real solution.
For this case we have the equation:
[tex]h = -16t ^ 2 + 25t + 6[/tex]
If we assume that the shoe reached the disc, then [tex]h = 14\ ft[/tex]
So:
[tex]14 = -16t ^ 2 + 25t + 6[/tex]
[tex]-16t ^ 2 + 25t + 6 -14 = 0\\\\-16t ^ 2 + 25t -8 = 0\\\\a = -16\\\\b = 25\\\\c = -8[/tex]
Then the discriminant is:
[tex]25^2 -4(-16)(- 8) = 113[/tex]
The discriminant is greater than 0. Then the equation has 2 real solutions. [tex]t_1[/tex] and [tex]t_2[/tex].
This means that if there are values of t for which [tex]h = 14\ ft[/tex]. In other words, this means that the shoe reached the disc.
In fact if you use the quadratic formula to solve the equation you will get:
[tex]t_1 = 1.11\ s[/tex]
[tex]t_2 = 0.450\ s[/tex]