Answer: 4. 18 feet per second
The average rate of change for h(t) between t = 0 and t = 2 is given by:
[tex]\frac{h\left(2\right)-h\left(0\right)}{2-0}=\frac{h\left(2\right)-h\left(0\right)}{2}[/tex].
Using the given expression:
[tex]h\left(2\right)=-16\left(2\right)^{2}+50\left(2\right)+3=39[/tex]
[tex]h\left(0\right)=-16\left(0\right)^{2}+50\left(0\right)+3=3[/tex]
So the average rate of change for h(t) between t = 0 and t = 2 is:
[tex]\frac{h\left(2\right)-h\left(0\right)}{2}=\frac{39-3}{2}=\frac{36}{2}=18[/tex] feet per second.
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