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Solve the quadratic equation numerically (using tables of x- and y- values).

x(x + 5) = 0
a.
x = -1 or x = 3
c.
x = -6 or x = 1
b.
x = 0 or x = -5
d.
x =1 or x = -1


Please select the best answer from the choices provided

A
B
C
D

Respuesta :

laurellee27

(x) (x + 5) = 0

Therefore:

  • x = 0

  • x + 5 = 0
  • x = 0 - 5
  • x = -5

b.  x = 0 or x = -5

Answer:

[tex]\text{The solution is }x=0\text{ or }x=-5[/tex]

Option b is correct.                

Step-by-step explanation:

Given the quadratic equation

[tex]x(x + 5) = 0[/tex]

we have to solve the above equation.

[tex]Equation: \thinspace x(x + 5) = 0[/tex]

[tex]x(x + 5) = 0[/tex]

By zero product property which states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0.

⇒ [tex]x=0\text{ or }x+5=0[/tex]

[tex]x=0\text{ or }x=-5[/tex]

Hence, option b is correct.

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