Answer:
[tex]A = 54 \, \sqrt{3} + 18 \, \sqrt{91}[/tex]
Step-by-step explanation:
Total area of a right hexagonal pyramid is computed as follows:
[tex]A = \frac{3 \sqrt{3}}{2} \, a^2 + 3 \, a \sqrt{h^2 + \frac{3 \, a^2}{4}}[/tex]
where a is the base edge and h is the height. Replacing with a = 6 and h = 8 we get:
[tex]A = \frac{3 \sqrt{3}}{2} \, 6^2 + 3 \, 6 \, \sqrt{8^2 + \frac{3 \, 6^2}{4}}[/tex]
[tex]A = 54 \, \sqrt{3} + 18 \, \sqrt{91}[/tex]
