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The point-slope from of the equation of the line that passes through (-4, -3) and (12, 1) is y- 1 = 1/4 (x - 12). What is the standard from of the equation from this line?

Respuesta :

gmany

Answer:

[tex]\large\boxed{x-4y=8}[/tex]

Step-by-step explanation:

The standard form of an equation of a line:

[tex]Ax+By=C[/tex]

We have the equation in point-slope form. Convert:

[tex]y-1=\dfrac{1}{4}(x-12)[/tex]             multiply both sides by 4

[tex]4y-4=x-12[/tex]              add 4 to both sides

[tex]4y=x-8[/tex]            subtract x from both sides

[tex]-x+4y=-8[/tex]             change the signs

[tex]x-4y=8[/tex]

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