Respuesta :

Answer: [tex](2m+n)(3m+11n)[/tex]

Step-by-step explanation:

[tex]a(x-\dfrac{-b-\sqrt{b^2-4ac} }{2a} )[/tex]

[tex]a(x+\dfrac{-b-\sqrt{b^2-4ac} }{2a} )[/tex]

[tex]6(m-\dfrac{-25n+\sqrt{(25n)^2-4*6*11n^2} }{2*6} )[/tex] [tex]6(m+\dfrac{-25n+\sqrt{(25n)^2-4*6*11n^2} }{2*6} )[/tex]

[tex](2m+n)(3m+11n)[/tex]

zainebamir540

Answer:

(3m+11n)(2m+n)

Step-by-step explanation:

We have given a expression.

6m²+25mn+11n²

We have to factorize above expression.

Splitting the middle term of above expression so that the sum of two terms should be 25 and their product be 66.

6m²+22mn+3mn+11n²

Making groups, we have

2m(3m+11n)+n(3m+11n)

Taking 3m+11n as common, we have

(3m+11n)(2m+n) which is the answer.

Otras preguntas