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contestada

Let f(x) = x^2 + -8x + 19 what is the minimum value of the function? Enter your answer in the box

Respuesta :

laurellee27

(4,3)

Function Template

ax^2 + bx + c

x^2 + -8x + 19

Max/Min Point Template

- (b / 2a)

- (-8 / 2 * 1)

- (-8 / 2)

- (-4)

4

Substitute the value into the function.

(x) = x^2 + -8x + 19

f(4) = 4^2 + -8(4) + 19

f(4) = 16 + (-32) + 19

f(4) = 3

Minimum point = (4,3)

Anonymouslizard

Answer:

Let f(x) = x^2 + -8x + 19 what is the minimum value of the function? Enter your answer in the box?

Find the x-value the minimum occurs at. Use this value to find the minimum value.

(4,3)