Respuesta :
As we know that circumference of the sphere is given as
[tex]C = 4\pi R[/tex]
here we know that
[tex]R = 6.37 \times 10^6 m[/tex]
now we have
[tex]C = 4\pi (6.37 \times 10^6)[/tex]
[tex]C = 8\times 10^7 m[/tex]
[tex]C = 8 \times 10^4 km[/tex]
PART B)
surface area of the sphere is given as
[tex]A = 4\pi R^2[/tex]
[tex]R = 6.37 \times 10^3 km[/tex]
[tex]A = 4\pi (6.37\times 10^3)^2[/tex]
[tex]A = 5.1 \times 10^8 km^2[/tex]
PART C)
Volume of the sphere is given as
[tex]V = \frac{4}{3}\pi R^3[/tex]
here we have
[tex]V = \frac{4}{3}\pi(6.37 \times 10^3)^3[/tex]
[tex]V = 1.1 \times 10^{12} km^3[/tex]
Explanation:
Given that,
Radius of Earth, [tex]r=6.37\times 10^6\ m[/tex]
(a) It is not possible to find the circumference of the sphere. But if we consider an image of the Earth, its circumference is given by :
[tex]C=2\pi r[/tex]
[tex]C=2\pi \times 6.37\times 10^6[/tex]
[tex]C=40.01\times 10^6\ m[/tex]
[tex]C=40.01\times 10^3\ km[/tex]
(b) Surface area of a sphere is given by :
[tex]A=4\pi r^2[/tex]
[tex]A=4\pi (6.37\times 10^6)^2[/tex]
[tex]A=5.09\times 10^{14}\ m^2[/tex]
[tex]A=5.09\times 10^{11}\ km^2[/tex]
(c) Volume of the sphere is given by :
[tex]V=\dfrac{4}{3}\pi r^3[/tex]
[tex]V=\dfrac{4}{3}\pi (6.37\times 10^6)^3[/tex]
[tex]V=1.082\times 10^{21}\ m^3[/tex]
[tex]V=1.082\times 10^{18}\ km^3[/tex]
Hence, this is the required solution.
