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The point-slope form the equation of the line that passes through (-4,-3) and (12,1) is y-1=1/4(x-12). What is the standard form of the equation for this line?A. X-4y=8, B.x-4y=2, C. 4x-y=8,D. 4x-y=2

Respuesta :

hroscoe

Answer: The answer is A

Step-by-step explanation:

y-1 = 1/4(x - 12)

y-1 = 1/4x - 3

-1/4x + y + 2 = 0

Multiply the whole equation by -4 to get rid of fraction and negative in front of 1/4:

x -4y -8 = 0, which is also x - 4y = 8