Need answers fast plz

Answer:
Step-by-step explanation:
We have:
two right triangles with legs 4m and 6m
The area:
[tex]A_1=\dfrac{1}{2}(4)(6)=12\ m^2[/tex]
three rectangles
22m × 6m
The area:
[tex]A_2=22\cdot6=132\ m^2[/tex]
22m × 7.21m
The area:
[tex]A_3=22\cdot7.21=158.62\ m^2[/tex]
22m × 4m
The area:
[tex]A_4=22\cdot4=88\ m^2[/tex]
The Surface Area:
[tex]S.A.=2A_1+A_2+A_3+A_4[/tex]
Substitute:
[tex]S.A.=2(12)+132+158.62+88=402.62\ m^2[/tex]