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A footpath is to be constructed in a park in the shape of a parallelogram. When a coordinate plane is laid over a map of the park, the vertices of the footpath are (-4,2) (8,2) (11,7) and (-1,7). What is the perimeter of this path

Respuesta :

I believe the answer is A

segunare233

Answer: perimeter = 35.66 units

Explanation:

AB=8-(-4)=12

CD=11-(-1)=12

BD=√(11−8)²+(7−2)² = √=34

AC=√(−1−(−4))²+(7−2)² = √=34

Perimeter = AB + CD + BD + AC

perimeter=2×12+2√34 =24+2√34 = 35.66 units

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