Respuesta :
Answer:
Corey's throw is higher than Mark's throw by 20.31 feet
Step-by-step explanation:
The vertical height of the object is given by : -16t² + vt + d , where v is initial velocity and d is the initial height of the object.
Initial velocity of Mark = 60 ft/sec
Initial height of Mark's throw = 6 feet
Equation of vertical height : h(t) = -16t² + 60 t + 6
Now, maximum height is achieved at time when h'(t) = 0
⇒ -32t + 60 = 0
⇒ t = 1.875 seconds
Height of Mark's throw : h(1.875) = -16(1.875)² + 60×1.875 + 6
⇒ Height of Mark's throw = 62.25 feet
Initial velocity of Corey = 70 ft/sec
Initial height of Corey's throw = 6 feet
Equation of vertical height : h(t) = -16t² + 70 t + 6
Now, maximum height is achieved at time when h'(t) = 0
⇒ -32t + 70 = 0
⇒ t =2.1875 seconds
Height of Mark's throw : h(2.1875) = -16(2.1875)² + 70×2.1875 + 6
⇒ Height of Corey's throw = 82.56 feet
Hence, Corey's throw is higher than Mark's throw by : 82.56 - 62.25
= 20.31 feet
Answer:
Corey's throw is higher than Mark's throw by 20.31 feet
Step-by-step explanation:
The vertical height of the object is given by : -16t² + vt + d , where v is initial velocity and d is the initial height of the object.
Initial velocity of Mark = 60 ft/sec
Initial height of Mark's throw = 6 feet
Equation of vertical height : h(t) = -16t² + 60 t + 6
Now, maximum height is achieved at time when h'(t) = 0
⇒ -32t + 60 = 0
⇒ t = 1.875 seconds
Height of Mark's throw : h(1.875) = -16(1.875)² + 60×1.875 + 6
⇒ Height of Mark's throw = 62.25 feet
Initial velocity of Corey = 70 ft/sec
Initial height of Corey's throw = 6 feet
Equation of vertical height : h(t) = -16t² + 70 t + 6
Now, maximum height is achieved at time when h'(t) = 0
⇒ -32t + 70 = 0
⇒ t =2.1875 seconds
Height of Mark's throw : h(2.1875) = -16(2.1875)² + 70×2.1875 + 6
⇒ Height of Corey's throw = 82.56 feet
Hence, Corey's throw is higher than Mark's throw by : 82.56 - 62.25
= 20.31 feet
