Answer:
D) f(x) = x^2 - 4 ; x > 1
x^2 _3, x ≤ 1
Step-by-step explanation:
From the given graph, the graph of the function f(x) = x^2 - 4 start from x > 1.
The unfilled represents the open interval. Therefore, the domain of the function is (1, infinity), which represented by x > 1.
The graph of the function x^2 + 3, start from x ≤ 1.
The filled circle dot represents the closed interval. Therefore, the domain of the function is [1, -infinity) which represented by x ≤ 1
Therefore, the answer is D)
f(x) = x^2 - 4 ; x > 1
x^2 _3, x ≤ 1
