Respuesta :

answer

4x

steps

[tex]x+2 + (4x-\frac{x^2+6x+8}{x+4} )[/tex]

factor x^2 + 6x + 8

product=8 and sum =6

4 times 2 = 8

4 + 2= 6

(x+4)(x+2)

[tex]x+2 + (4x-\frac{(x+4)(x+2)}{x+4} )[/tex]

Cancel out x+4 at the top and bottom

x + 2 +(4x -(x+2))

Now we remove the parenthesis

x + 2+4x -x-2

4x

So the final answer is 4x


kudzordzifrancis

Answer:

[tex]4x[/tex]

Step-by-step explanation:

The given expression is

[tex]x+2+[4x-\frac{x^2+6x+8}{x+4} ][/tex]

Let us first of all split the middle term of the quadratic trinomial to get,

[tex]=x+2+[4x-\frac{x^2+2x+4x+8}{x+4} ][/tex]


We simplify to get;

[tex]=x+2+[4x-\frac{x(x+2)+4(x+2)}{x+4} ][/tex]

We factor to obatin,

[tex]=x+2+[4x-\frac{(x+2)(x+4)}{x+4} ][/tex]


We cancel the common factor to get,


[tex]=x+2+[4x-(x+2)][/tex]


This simplifies to,

[tex]=x+2+4x-x-2[/tex]


This gives us,

[tex]=4x[/tex]








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