contestada

Find an equation in standard form of the parabola that passes through (-2, 9), (-4, 5), and (1, 0)

Respuesta :

Answer:

We know the parabolic function:

[tex]y=ax^2+bx+c[/tex]

We will use the points to form the equation (-2,9) we will get:

[tex]9=a(-2)^2+b(-2)+c[/tex]

[tex]9=4a-2b+c[/tex]

Now, using (-4,5) we will get:

[tex]5=16a-4b+c[/tex]

Now, using (1,0) we will get:

[tex]0=a+b+c[/tex]

Now, using these three equations we will find a,b and c

On solving equations: a=-1,b=-4 and c=5

Now, using a,b and c in the general equation we get:

[tex]y=(-1)x^2+(-4)x+5[/tex]

[tex]\Rightarrow y=-x^2-4x+5[/tex]