Answer:
Option A. [tex]\sqrt{53}[/tex]
Step-by-step explanation:
In this figure side AB is a part of triangle formed diagonal of base of the box.
Side with length 1 unit and side AB.
Now we will calculate the length of diagonal of the base
= [tex]\sqrt{4^2+6^2}[/tex] [By Pythagoras theorem]
= [tex]\sqrt{16+36}[/tex]
= [tex]\sqrt{52}[/tex]
Now we apply Pythagoras Theorem again.
AB² = 1² + ([tex]\sqrt{52}[/tex])²
= 1 + 52
= 53
AB = [tex]\sqrt{53}[/tex]
Option A is the answer.
