The solubility of Oxygen at given temperature (12 ∘c) is 10.766 mg/ L
The moles of oxygen in one litre will be
[tex]moles of oxygen = \frac{mass}{molar mass} = \frac{10.766mg}{32} = 0.336 mmoles[/tex]
Molarity is moles of solute per litre of solution
so molarity will be
[tex]Molarity = \frac{0.336 mmoles}{1 L} = 0.336 X 10^{-3} M[/tex]