When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 15.6 g of carbon were burned in the presence of 59.1 g of oxygen, 17.5 g of oxygen remained unreacted. What mass of carbon dioxide was produced?

Question

15-01-2019
Chemistry

contestada

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 15.6 g of carbon were burned in the presence of 59.1 g of oxygen, 17.5 g of oxygen remained unreacted. What mass of carbon dioxide was produced?

Respuesta :

Otras preguntas

A relation is given below. {(0, 0), (2, 0.5), (4, 1), (3, 1.5), (4, 2), (5, 1.5), (6, 8)} Which ordered pair can be removed to make this relation a function? Wh

list down 20 human rights

Multiply Conjugates Using the Product of Conjugates Pattern In the following exercises, multiply each pair of conjugates using the Product of Conjugates Pattern

One of the applications of proximate cause doctrine to cases where a plaintiff sues for negligence require: Group of answer choices a defendant to prove that he

A restraint that provides protection without having to be handled by the occupant is called.

From laboratory measurements, we know that a particular spectral line formed by hydrogen appears at a wavelength of 500 nanometers (nm). The spectrum of a parti

Jessie has always enjoyed fixing things and has a high degree of mechanical aptitude. Currently, she is employed as a jet mechanic at a military base. Jessie is

69. REAL-WORLD APPLICATIONS A gym membership with two personal training sessions costs $125, while gym membership with five personal training sessions costs $26

When the sarcomere contracts and shortens, __________. When the sarcomere contracts and shortens, __________. the I-band becomes larger the zones of overlap bec

epresents a single pathway through which energy and matter flow _____ 2. feeding positions in a food chain or web _____ 3. the living aspects of the environment

IlaMends IlaMends · Answer 1 · 2019-01-15T07:09:12+01:00

Answer: 5.72 g mass of carbon dioxide was produced

Explanation:

[tex]C+O_2\rightarrow CO_2[/tex]

Moles of C =[tex]\frac{\text{mass of carbon}}{\text{molar mass of carbon}}=\frac{15.6 g}{12 g/mol}=1.3 moles[/tex]

Mass of [tex]O_2[/tex] reacted = 59.1 g - 17.5 g = 41.6 g

Moles of [tex]O_2\text{ reacted}=\frac{\text{mass of}O_2}{\text{molar mass of}O_2}=\frac{41.6 g}{32 g/mol}=1.3 moles[/tex]

According to reaction 1 mole [tex]O_2[/tex] produces 1 mole of [tex]CO_2[/tex] then 1.3 mole of [tex]O_2[/tex] will produce [tex]\frac{1}{1}\times 1.3[/tex] moles of [tex]CO_2[/tex]

Mass of [tex]CO_2[/tex]:

=Moles of [tex]CO_2[/tex] × molar mass of[tex]CO_2[/tex] = 1.3 ×44 g/mol =

=57.2 grams

5.72 g mass of carbon dioxide was produced