The force of gravity between two objects is given by Fg =
−Gm1m2
r2
, where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the objects' centers. Find the vertical asymptote of the graph of the function and explain its meaning in context.

so the question is equivalent to asking what is the asymptote of 1/r^2 as r approaches 0, The asymptote is the y axis as shown in the attachment where 1/r^2 is graphed.

Thank you,

MrB

Answer Link

Аноним Аноним · Answer 2 · 2019-06-19T13:20:53+02:00

Answer with explanation:

The force of gravity between two objects is given by

[tex]F_{g}=\frac{-Gm_{1}m_{2}}{r^2}[/tex]

Replacing , force by , y and product of -G the gravitational constant, masses [tex]m_{1}, m_{2}[/tex] by t,the above equation reduces to,

[tex]y=\frac{t}{x^2}[/tex]

Horizontal Asymptote, is, y=0

[tex]y= \lim_{x \to \infty} f(x)\\\\y = \lim_{x \to \infty} \frac{1}{x^2}\\\\y=0[/tex]

And Vertical Asymptote is, x=0

[tex]x= \lim_{y \to \infty} f(y)\\\\x = \lim_{y \to \infty} \frac{-1}{\sqrt{y}}\\\\x=0[/tex]

The meaning of vertical asymptote in context of the graph of the function is ,that when Distance between two objects reduces to Zero, the force of attraction between two bodies, reduces to zero.

The force of gravity between two objects is given by Fg = −Gm1m2 r2 , where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the objects' centers. Find the vertical asymptote of the graph of the function and explain its meaning in context.

Respuesta :

Otras preguntas

The force of gravity between two objects is given by Fg =
−Gm1m2
r2
, where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between the objects' centers. Find the vertical asymptote of the graph of the function and explain its meaning in context.