[tex]\text{The formula of an area of a triangle:}\\\\A_\triangle=\dfrac{1}{2}bh\\\\b-base\\h-height\\----------------------\\\\\text{We have}\\\\b=41\dfrac{1}{2}ft=\dfrac{41\cdot2+1}{2}ft=\dfrac{83}{2}ft\\\\h=36ft\\\\\text{Substitute:}\\\\A_\triangle=\dfrac{1}{2}\left(\dfrac{83}{2}\right)(36)=\left(\dfrac{83}{\not4_1}\right)(36\!\!\!\!\!\!\diagup^9)=(83)(9)=747\ ft^2\\\\\\Answer:\ \boxed{A_\triangle=747\ ft^2}[/tex]
