Solution:
Equation of line in intercept form , if it cuts X axis at (a,0) and Y axis at (0,b) is :
= [tex]\frac{x}{a} +\frac{y}{b}=1[/tex]
So, equation of line passing through (-5,0) and (0,-5) is
= [tex]\frac{x}{-5} +\frac{y}{-5}=1[/tex]
→x + y = -5
→→y= -x -5
Comparing with slope intercept form of line which is , y= m x + c
m =-1
tanФ=-1
tanФ=tan 135°
Ф= 135°
The angle made by line x+y =-5 with positive direction of x- axis is 135° or [tex]\frac{135\pi }{180}=\frac{3\pi}{4}[/tex] in terms of Radian.