contestada

An upward force act on a proton as it moves with a speed of 2.0 x 10^5 meters/seconds through a magnetic field of 8.5 x 10^2

Respuesta :

Force on a moving charge is given by formula

[tex]\vec F = q(\vec v \times \vec B)[/tex]

here we know that this force will be maximum when velocity is perpendicular to magnetic field

[tex]\vec F = qvB[/tex]

here we know that

[tex]v = 2.0 \times 10^5 m/s[/tex]

[tex]q = 1.6 \times 10^{-19} C[/tex]

[tex]B = 8.5 \times 10^2 T[/tex]

now we have

[tex]F = (1.6 \times 10^{-19})(2 \times 10^5)(8.5 \times 10^2) [/tex]

[tex]F = 2.72 \times 10^{-11} N[/tex]