Which function could be a stretch of the exponential decay function shown on the graph

Answer:
Option C is correct.
[tex]f(x) = 2(\frac{1}{6})^x[/tex]
Step-by-step explanation:
Exponential function is given by:
[tex]f(x) = ab^x[/tex] where a is the initial value and b is the growth factor.
Vertically Stretch:
A function f(x) = kg(x)
From the given options only option C is correct, i.,e [tex]f(x) = 2(\frac{1}{6})^x[/tex]
As
[tex]b = \frac{1}{6} < 1[/tex]
[tex]|k| = 2 > 1[/tex]
⇒the function [tex]f(x) = 2(\frac{1}{6})^x[/tex] could be stretch of the exponential decay function.