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A 2,000-kg test car, traveling 60 m/s hits a brick wall. Using motion pictures, the time involved is determined to be 0.050 s. What is the change in momentum of the car?

A) +1.2 x 10^5

B)-1.2 x 10^5

Respuesta :

change in momentum of car is given as

[tex]\Delta P = P_f - P_i[/tex]

here we have

[tex]\Delta P = m(v_f - v_i)[/tex]

given that

m = 2000 kg

[tex]v_f = 0[/tex]

[tex]v_i = 60 m/s[/tex]

now we have

[tex]\Delta P = 2000(0 - 60) [/tex]

[tex]\Delta P = - 1.2 \times 10^5 kg m/s[/tex]

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