Answer:
Option B is correct.
Step-by-step explanation:
We have been given that 3 lottery games have decided to play
So, here we have total possibility of numbers s between 0 and 9 which is total of 10 numbers
And number can be chosen more than once.
So, the probability will be [tex]\frac{1}{10}\cdot \frac{1}{10}\cdot \frac{1}{10}[/tex]
On simplification we will get
the probability of winning [tex]\frac{1}{1000}[/tex]
Therefore, option B is correct.
