Answer:
Jeff's ribbon is, [tex]\frac{3}{5}[/tex] feet long
Step-by-step explanation:
Let J represents the length of Jeff ribbon and B represents the length of Bill ribbon.
As per the condition:
Jeff's ribbon is 3/7 the length of Bill's ribbon.
⇒ [tex]J = \frac{3}{7}B[/tex] ......[1]
It is also given that: if both ribbons combined are 2 feet long.
⇒J + B = 2 ......[2]
Substitute the equation [1] into [2] we get;
[tex]\frac{3}{7}B+B = 2[/tex]
Simplify:
[tex]\frac{10}{7}B = 2[/tex]
Multiply both sides by [tex]\frac{7}{10}[/tex] we get;
[tex]B = \frac{7}{5}[/tex] ribbons
Substitute the value of B in equation [1] we have;
[tex]J = \frac{3}{7} \times \frac{7}{5}= \frac{3}{5}[/tex] feet
Therefore, Jeff's ribbon is, [tex]\frac{3}{5}[/tex] feet long
