Respuesta :
Answer:
Carlos hit 36 runs
Marty hits 37 home runs
Andrew hit 35 home runs
Step-by-step explanation:
Given :
Let M represents the Marty , C represents the Carlos and A represents the Andrew.
Now we are given that In one season Marty, Carlos, Andrew hit a total of 108 home run
⇒ M+C+A=108 --a
we are also given that Marty and Andrew together hit twice as many home runs as did Carlos,
⇒M+A=2C ---b
Also, Carlos had one more home run than Andrew.
⇒C=1+A --c
Now put equation b in a
⇒2C+C=108
⇒3C=108
⇒C=108/3
⇒C=36
Thus Carlos hit 36 runs
Put value of C in equation c
⇒ 36=A+1
⇒35=A
Thus Andrew hit 35 home runs
Now put values of A and C in equation a to get value of M
M+36+35=108
M+71=108
M=108-71=37
Thus Marty hits 37 home runs
Hence Carlos hit 36 runs
Marty hits 37 home runs
Andrew hit 35 home runs
Answer:
Let M represents the Marty , C represents the Carlos and A represents the Andrew.
As per the given statement:
In one season Marty, Carlos, Andrew hit a total of 108 home runs
⇒ [tex]M+C+A = 108[/tex] ......[1]
It is also given that Marty and Andrew together hit twice as many home runs as did Carlos,
⇒[tex]M+A = 2C[/tex] ......[2]
Also, Carlos had one more home run than Andrew.
⇒[tex]C = A+1[/tex] .....[3]
Substitute equation [2] into [1] we get;
[tex]2C+ C = 108[/tex]
Combine like terms;
[tex]3C = 108[/tex]
Divide both sides by 3 we get;
C = 36 hit home runs
Substitute the value of C in [3] we have;
[tex]36 = A + 1[/tex]
Subtract 1 from both sides we get;
A = 35 hit home runs
Substitute the value of A and C in [1] we have;
[tex]M+36+35 = 108[/tex]
or
[tex]M+71 = 108[/tex]
Subtract 71 from both sides we get;
[tex]M = 37[/tex] hit home runs.
Therefore, each player hit:
Carlos = 36 hit home runs
Andrew = 35 hit home runs
And
Marty = 37 hit home runs.
