Answer:
EB is bisected by DF Option A
A is the midpoint of FC Option B
EB is a segment bisector Option D
FA = 1/2FC Option E
Step-by-step explanation:
In the given question:
ED ≅ DB (ED is congruent to DB)
and a diagram, it shows:
Line segment EB and point D & A on the line segment EB.
FD is another line segment and FC cuts the line segment at point A such that, FA is equal to AC.
It means A is the mid point of FC.
and EB defined as angle bisector of FC.
DF is also bisector of EB.
So,
EB is bisected by DF Option A
A is the midpoint of FC Option B
EB is a segment bisector Option D
FA = 1/2FC Option E
Above options are correct for given figure.
