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The length of a rectangular field is 16 feet less than twice the width. What is the width of the field if its area is 1916 square feet? (98 points!!!!)

Respuesta :

mathecoach

Answer:

L = 2W - 16

A = L * W = 1916

(2W - 16) * W = 1916

2W^2 - 16W = 1916

2W^2 - 16W - 1916 = 0

W^2 - 8W - 958 = 0 --> W = 35.21 feet

Answer:

W = 35.21 ft

Step-by-step explanation:

L = 2W - 16  =1916

(2W - 16) x W = 1916

2W^2 - 16W = 1916

2W^2 - 16W - 1916 = 0

W^2 - 8W - 958 = 0

W = 35.21 feet

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