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Let the first and smaller number be x. Since the second number is 5 times the first, the second number is 5x. We also know both of these numbers must add to 50; thus, we can create the following equation.

[tex]x+5x=50[/tex]

Combine like terms

[tex]6x = 50[/tex]

Divide both sides by 6

[tex]x = 50/6 = 25/3 \approx 8.333[/tex]

This is the value of the first number. The number you're looking for isn't specified in the question description, so I'll just provide the value of the second number. The second number has to be 5 times the first.

Thus, we just multiply 5 to x.

[tex]5x = 5(25/3) = 125/3 \approx 41.667[/tex]

That's the value of the second number.

nam3ra
Let the first number be x, and the second 5x. The second is five times the first, so thats why it is 5x. Now, add x+5x=50. Simplify the equation to be 6x=50, because x+5x is 6x. Do the opposite of multiplyig because 6x is the same as 6 times x. Divide 6 on both sides. 50 divided by six is your first number (x). Now multiply your quotient by 5 to find the second number, and those are your two numbers.