Answer:
[tex]y+2=\frac{1}{2}(x+3)[/tex]
Step-by-step explanation:
point slope form for the line parallel to [tex]y=\frac{1}{2}x-7[/tex] that passes through (-3,-2)
First find the slope of the given line
Given line is in the form of [tex]y=mx+b[/tex]
slope of given line = [tex]\frac{1}{2}[/tex]
slope of parallel line = slope of given line
Slope of parallel line = [tex]\frac{1}{2}[/tex]
Point slope form of a line is
[tex]y-y_1 = m(x-x_1)[/tex], point is (-3,2)
[tex]y+2=\frac{1}{2}(x+3)[/tex]
