Answer: 5.23 inches
Step-by-step explanation:
Let the length of the arc intersected by a central angle x be l.
Given:- Central angle[tex]x=\frac{\pi}{6}\text{ radians}[/tex]
Radius r= 10 inches
We know that ,
[tex]l=x\ r\\\\\Rightarrow\ l=\frac{\pi}{6}\times10\\\\\Rightarrow\ l=\frac{3.14\times10}{6}= 5.2333333333\approx5.23\text{ inches}[/tex]
Thus, the length of the arc of a central angle [tex]\frac{\pi}{6}\text{ radians}[/tex] is 5.23 inches.
