Answer:
8.2 m/s
Explanation:
The horizontal component of the velocity is given by:
[tex]v_x = v cos \theta[/tex]
where
v = 10 m/s is the magnitude of the velocity
[tex]\theta=35^{\circ}[/tex] is the angle at which the ball has been thrown, with respect to the horizontal
Substituting the values into the equation, we get
[tex]v_x=(10 m/s)(cos 35^{\circ})=8.2 m/s[/tex]
