A student throws a coin vertically downward from the top of a building. The coin leaves the throwers hand with a speed of 15.0 m/s. What is the magnitude of its velocity after falling 10.0 m?
A.) 18.0 m/s
B.) 14.5 m/s
C.) 20.5 m/s
D.) 19.8 m/s

We have the equation of motion, [tex]v^2=u^2+2as[/tex], where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.

Here initial velocity = 15 m/s

Displacement = 10 m

Acceleration = acceleration due to gravity = 9.8 m/s²

Substituting to get final velocity,

[tex]v^2=u^2+2as\\ \\ \\v^2=15^2+2*9.8*10\\ \\ v=20.52m/s[/tex]

So the correct answer is option C

A student throws a coin vertically downward from the top of a building. The coin leaves the throwers hand with a speed of 15.0 m/s. What is the magnitude of its velocity after falling 10.0 m? A.) 18.0 m/s B.) 14.5 m/s C.) 20.5 m/s D.) 19.8 m/s

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A student throws a coin vertically downward from the top of a building. The coin leaves the throwers hand with a speed of 15.0 m/s. What is the magnitude of its velocity after falling 10.0 m?
A.) 18.0 m/s
B.) 14.5 m/s
C.) 20.5 m/s
D.) 19.8 m/s