Respuesta :

frika

Answer:

[tex]\ast=16a^2[/tex]

Step-by-step explanation:

Use formula for  a square of a sum:

[tex](x+y)^2=x^2+2xy+y^2.[/tex]

Note that

  • [tex]49=7^2;[/tex]
  • [tex]56a=2\cdot 28a=2\cdot 7\cdot 4a.[/tex]

Then instead of * should be the square of the term 4a that is [tex](4a)^2=16a^2.[/tex]

Then

[tex]16a^2+56a+49=(4a+7)^2.[/tex]

A n s w e r :

1 6 a ^2